70-761 対応受験、070-761 試験対策書

 

NO.1 Note: This question is part of a series of questions that present the same scenario. Each
question in the series contains a unique solution that might meet the stated goals. Some question
sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section. You will NOT be able to return to it. As a result, these
questions will not appear in the review screen.
You have a database that includes the tables shown in the exhibit (Click the Exhibit button.)
You need to create a Transact-SQL query that returns the following information:
- the customer number
- the customer contact name
- the date the order was placed, with a name of DateofOrder
- a column named Salesperson, formatted with the employee first name, a space, and the employee
last name
- orders for customers where the employee identifier equals 4
The output must be sorted by order date, with the newest orders first.
The solution must return only the most recent order for each customer.
Solution: You run the following Transact-SQL statement:
Does the solution meet the goal?
A. Yes
B. No
Answer: A

070-761 価値   070-761 対策   
Explanation:
The MAX(orderdate) in the SELECT statement makes sure we return only the most recent order.
A WHERE o.empiD =4 clause is correctly used.
GROUP BY is also required.

NO.2 Note: This question is part of a series of questions that use the same or similar answer choices.
An answer choice may be correct for more than one question in the series. Each question is
independent of the other questions in this series. Information and details provided in a question
apply only to that question.
You have a table named Products that contains information about the products that your company
sells. The table contains many columns that do not always contain values.
You need to implement an ANSI standard method to convert the NULL values in the query output to
the phrase "Not Applicable".
What should you implement?
A. a stored procedure
B. the COALESCE function
C. the ISNULL function
D. a table-valued function
E. the TRY_CONVERT function
F. a scalar function
G. a view
H. the TRY_PARSE function
Answer: C

070-761 キャリアパス   070-761 過去   
Explanation:
The ISNULL function replaces NULL with the specified replacement value.
References: https://msdn.microsoft.com/en-us/library/ms184325.aspx

NO.3 You have a database that stored information about servers and application errors. The
database contains the following tables.
Servers
Errors
You need to return all error log messages and the server where the error occurs most often.
Which Transact-SQL statement should you run?
A. Option D
B. Option B
C. Option A
D. Option C
Answer: D

070-761 日本語   070-761 エンジン   

NO.4 Note: This question is part of a series of questions that use the same or similar answer choices.
An answer choice may be correct for more than one question in the series. Each question is
independent of the other questions in this series. Information and details provided in a question
apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and
tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following
columns:
You need to run a query to find the total number of customers who have both deposit and loan
accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
B. CustNo IS NULL
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
D. CustNo
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
H. CustNo = L.CustNo
I. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
J. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
Answer: J

070-761 改訂   
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However,
it only returns the rows selected by all queries or data sets. If a record exists in one query and not in
the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

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70-761試験番号:70-761
試験科目:「Querying Data with Transact-SQL
一年間無料で問題集をアップデートするサービスを提供いたします
最近更新時間:2017-07-17
問題と解答:全85問 70-761 対応受験

>> 70-761 対応受験

 
070-761試験番号:070-761
試験科目:「Querying Data with Transact-SQL
一年間無料で問題集をアップデートするサービスを提供いたします
最近更新時間:2017-07-17
問題と解答:全85問 070-761 試験対策書

>> 070-761 試験対策書

 

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